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PA113: ELECTRICITY & MAGNETISM



Solving Problems in Electrostatics




You must know how to:



READ THE QUESTION CAREFULLY!

Calculating the Electric Field. I

1) E due to charged particle distribution


E =  1

4pe0

å
i 
 Qi

ri2
 
^
ri
 

Use vector sum for each charge, where for each charge:



Example:
Charges +Q, +2Q, -5Q and +2Q are placed at the four corners ABCD respectively of a square of side a. Find the electric field strength at the center of the square.

Calculating the Electric Field. II

2) Coulomb's Law for a continuous charge distribution


F12 =  1

4pe0
 Q1 Q2

r2
 
^
r
 
  ;       E =  F

q0
=  1

4pe0
 Q

r2
 
^
r
 

Continuous may mean a line, ring, sheet or volume.



Follow tips on pp. 712-713

Example: (similar to example on p.689)
Show that Ez at distance z along the z-axis from a long, straight, uniform line charge of length 2l centered at the origin and oriented along the z-axis is given by


 ll

[2pe0 (z2 - l2)]

where z > l.

Calculating the Electric Field. III

3) Using Gauss's Law to find E


Fnet = ó
(ç)
õ



S 
En dA =  Qinside

e0

Most useful if charge distribution is highly symmetric



Follow tips on pp. 712-713


Study Chapter 23 examples - classic exam-type questions.

Example
Determine E inside and outside a thin, uniformly charged sphere of radius R and total charge Q



Example
Determine E inside and outside a uniform, spherical distribution of charge of radius R and total charge Q

Example:

Consider two concentric shells of radii a and b with uniform surface charge densities sa and sb. They have equal and opposite total charge Qa = -Q and Qb = +Q where Q > 0.

(a) develop expressions for the electric field in all three regions of space: r < a, a < r < b and r > b, where r is the distance from the centre of the spheres.

(b) draw a graph of E versus r from r=0 to r=3a for the case where b=2a.





Example:

A straight, thin wire filament 12m long with Q = -74 nC and uniform linear charge density is coaxial with a neutral conducting pipe of the same length; the inner radius is 6.0 mm and the outer radius is 9.0 mm.

(a) Estimate the induced surface charge densities of the inner and outer surfaces of the pipe.

(b) For points in the perpendicular bisector plane, make a graph of E versus R in the range 1 to 15 mm, where R is the perpendicular distance from the filament.

Calculating the Electric Potential


V =  U

Q0
  ;       U(r) = - ó
õ
r

¥ 
F ·dl  ;       V(r) = - ó
õ
r

¥ 
E ·dl

For a system of charged particles
V =  1

4pe0

å
i 
 qi

ri

For a continuous distribution of charge


V =  1

4pe0
ó
õ
 dq

r


We will only deal with simple cases (planes, spheres, etc.)

Need to understand V, U and how to derive E from V.



Example:

Determine the electric potential inside and outside a
uniform, spherical distribution of charge of radius r0 and
total charge Q

Example

Consider a uniformly charged rod of length 2l and linear charge density l (=Q/2l) centered at the origin and orientated along the z-axis. Show that the potential at points in the perpendicular bisector plane (the xy plane) is


V =  l

2pe0
  ln
l +
Ö

l2 + R2

R

where R = Ö{x2 + y2}.




File translated from TEX by TTH, version 3.01.
On 4 Nov 2002, 17:22.